Resposta:
Sejam as equivalências das escalas termométricas °C, K e °F dada por:
[tex]\frac{T_{C}}{5} =\frac{T_{F}-32}{9} =\frac{T_{K}-273}{5}[/tex]
a) [tex]\frac{T_{C}}{5} =\frac{312-32}{9} =\frac{T_{K}-273}{5}[/tex]
[tex]\frac{T_{C}}{5} =\frac{312-32}{9}\ ; T_{C} =\frac{(5).280}{9} = 155,55\°C[/tex]
[tex]\frac{312-32}{9} =\frac{T_{K}-273}{5}\ ; T_{K}=155,55+273 =428,55\ K[/tex]
b) (1/4) . 1200 = 300 °C
[tex]\frac{300}{5} =\frac{T_{F}-32}{9} =\frac{T_{K}-273}{5}[/tex]
[tex]\frac{300}{5} =\frac{T_{F}-32}{9}\ ; T_{F}=540+32 = 572\°F[/tex]
[tex]\frac{300}{5} =\frac{T_{K}-273}{5}\ ;T_{K}=300+273=573\ K[/tex]
c) [tex]\frac{T_{C}}{5} =\frac{T_{F}-32}{9} =\frac{773-273}{5}[/tex]
[tex]\frac{T_{C}}{5} =\frac{773-273}{5}\ ; T_{C}=500\°C[/tex]
[tex]\frac{T_{F}-32}{9} =\frac{773-273}{5}[/tex]
[tex]T_{F} =900+32=932\°F[/tex]